2/3(m-1)-3/4(2m-1)=1-3/2(3m-1)

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Solution for 2/3(m-1)-3/4(2m-1)=1-3/2(3m-1) equation: 



2/3(m-1)-3/4(2m-1)=1-3/2(3m-1)

We move all terms to the left:

2/3(m-1)-3/4(2m-1)-(1-3/2(3m-1))=0



Domain of the equation: 3(m-1)!=0

m∈R





Domain of the equation: 4(2m-1)!=0

m∈R





Domain of the equation: 2(3m-1))!=0

m∈R



We calculate fractions


(-18m^2m/(3(m-1)*4(2m-1)*2(3m-1)))+(-(-36m^2m)/(3(m-1)*4(2m-1)*2(3m-1)))+(16m^22/(3(m-1)*4(2m-1)*2(3m-1)))=0



We calculate terms in parentheses: +(-18m^2m/(3(m-1)*4(2m-1)*2(3m-1))), so:

-18m^2m/(3(m-1)*4(2m-1)*2(3m-1))

We multiply all the terms by the denominator


-18m^2m

Back to the equation:

+(-18m^2m)





We calculate terms in parentheses: +(-(-36m^2m)/(3(m-1)*4(2m-1)*2(3m-1))), so:

-(-36m^2m)/(3(m-1)*4(2m-1)*2(3m-1))

We multiply all the terms by the denominator


-(-36m^2m)

We get rid of parentheses

36m^2m

Back to the equation:

+(36m^2m)





We calculate terms in parentheses: +(16m^22/(3(m-1)*4(2m-1)*2(3m-1))), so:

16m^22/(3(m-1)*4(2m-1)*2(3m-1))

We do not support empression: m^22

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