2/3(m+4)=1/5(3m+9)

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Solution for 2/3(m+4)=1/5(3m+9) equation: 



2/3(m+4)=1/5(3m+9)

We move all terms to the left:

2/3(m+4)-(1/5(3m+9))=0



Domain of the equation: 3(m+4)!=0

m∈R





Domain of the equation: 5(3m+9))!=0

m∈R



We calculate fractions


(10m3/(3(m+4)*5(3m+9)))+(-3mm/(3(m+4)*5(3m+9)))=0



We calculate terms in parentheses: +(10m3/(3(m+4)*5(3m+9))), so:

10m3/(3(m+4)*5(3m+9))

We multiply all the terms by the denominator


10m3

We add all the numbers together, and all the variables

10m^3

We do not support empression: m^3

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