2/3(k-9)=4(k-19)

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Solution for 2/3(k-9)=4(k-19) equation: 


k in (-oo:+oo)

(2/3)*(k-9) = 4*(k-19) // - 4*(k-19)

(2/3)*(k-9)-(4*(k-19)) = 0

(2/3)*(k-9)-4*(k-19) = 0

2/3*(k-9)-4*(k-19) = 0

2/3*(k-9)-4*(k-19) = 0

70-10/3*k = 0

70-10/3*k = 0

70-10/3*k = 0 // - 70

-10/3*k = -70 // : -10/3

k = -70/(-10/3)

k = 21

k = 21

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