2/3(9x-6)=1/4912-4x)

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Solution for 2/3(9x-6)=1/4912-4x) equation: 



2/3(9x-6)=1/4912-4x)

We move all terms to the left:

2/3(9x-6)-(1/4912-4x))=0



Domain of the equation: 3(9x-6)!=0

x∈R





Domain of the equation: 4912-4x))!=0

We move all terms containing x to the left, all other terms to the right

-4x))!=-4912

x!=-4912/1

x!=-4912

x∈R



We add all the numbers together, and all the variables

2/3(9x-6)-(-4x+1/4912))=0

We get rid of parentheses

2/3(9x-6)+4x-1/4912)=0

We calculate fractions


4x+()/27x+(-3x9/27x=0

We multiply all the terms by the denominator


4x*27x+(-3x9+()=0



We calculate terms in parentheses: +(-3x9+(), so:

-3x9+(

We add all the numbers together, and all the variables

-3x^9

We do not support expression: x^9

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