2/3(9x-6)+1=7-2x+8

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Solution for 2/3(9x-6)+1=7-2x+8 equation: 



2/3(9x-6)+1=7-2x+8

We move all terms to the left:

2/3(9x-6)+1-(7-2x+8)=0



Domain of the equation: 3(9x-6)!=0

x∈R



We add all the numbers together, and all the variables

2/3(9x-6)-(-2x+15)+1=0

We get rid of parentheses

2/3(9x-6)+2x-15+1=0

We multiply all the terms by the denominator


2x*3(9x-6)-15*3(9x-6)+1*3(9x-6)+2=0

Wy multiply elements

6x^2(9-45x(9+3x(9+2=0

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