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(2/3)*(9*x-(15*y)-3) = 0
(2/3)*(9*x-15*y-3) = 0
2/3*(9*x-15*y-3) = 0
( 2/3 )
2/3 = 0
x belongs to the empty set
( 9*x-15*y-3 )
9*x-15*y-3 = 0 // + -15*y-3
9*x = -(-15*y-3) // : 9
x = (-(-15*y-3))/9
x = (3-(-15*y))/9
x = (3-(-15*y))/9
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