2/3(9x+9)-8=-1/2(18x-4)

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Solution for 2/3(9x+9)-8=-1/2(18x-4) equation: 



2/3(9x+9)-8=-1/2(18x-4)

We move all terms to the left:

2/3(9x+9)-8-(-1/2(18x-4))=0



Domain of the equation: 3(9x+9)!=0

x∈R





Domain of the equation: 2(18x-4))!=0

x∈R



We calculate fractions


(4x1/(3(9x+9)*2(18x-4)))+(-(-3x9)/(3(9x+9)*2(18x-4)))-8=0



We calculate terms in parentheses: +(4x1/(3(9x+9)*2(18x-4))), so:

4x1/(3(9x+9)*2(18x-4))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-(-3x9)/(3(9x+9)*2(18x-4))), so:

-(-3x9)/(3(9x+9)*2(18x-4))

We add all the numbers together, and all the variables

-(-3x^9)/(3(9x+9)*2(18x-4))

We multiply all the terms by the denominator


-(-3x^9)

We do not support expression: x^9

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