2/3(9x+6)-12=16+1/8(16x-32)

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Solution for 2/3(9x+6)-12=16+1/8(16x-32) equation: 



2/3(9x+6)-12=16+1/8(16x-32)

We move all terms to the left:

2/3(9x+6)-12-(16+1/8(16x-32))=0



Domain of the equation: 3(9x+6)!=0

x∈R





Domain of the equation: 8(16x-32))!=0

x∈R



We calculate fractions


(16x1/(3(9x+6)*8(16x-32)))+(-3x9/(3(9x+6)*8(16x-32)))-12=0



We calculate terms in parentheses: +(16x1/(3(9x+6)*8(16x-32))), so:

16x1/(3(9x+6)*8(16x-32))

We multiply all the terms by the denominator


16x1

We add all the numbers together, and all the variables

16x

Back to the equation:

+(16x)





We calculate terms in parentheses: +(-3x9/(3(9x+6)*8(16x-32))), so:

-3x9/(3(9x+6)*8(16x-32))

We multiply all the terms by the denominator


-3x9

We add all the numbers together, and all the variables

-3x^9

We do not support expression: x^9

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