2/3(9c+9)-2c+3c=27

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Solution for 2/3(9c+9)-2c+3c=27 equation: 



2/3(9c+9)-2c+3c=27

We move all terms to the left:

2/3(9c+9)-2c+3c-(27)=0



Domain of the equation: 3(9c+9)!=0

c∈R



We add all the numbers together, and all the variables

c+2/3(9c+9)-27=0

We multiply all the terms by the denominator


c*3(9c+9)-27*3(9c+9)+2=0

Wy multiply elements

3c^2(9-81c(9+2=0

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