2/3(9-x)1/3x

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Solution for 2/3(9-x)1/3x equation: 


x in (-oo:+oo)

(2/3)*(9-x) < (1/3)*x // - (1/3)*x

(2/3)*(9-x)-((1/3)*x) < 0

(2/3)*(9-x)+(-1/3)*x < 0

2/3*(9-x)-x/3 < 0

(2/3*3*(9-x))/3-x/3 < 0

2/3*3*(9-x)-x < 0

18-3*x < 0

(18-3*x)/3 < 0

(18-3*x)/3 < 0 // * 3^2

3*(18-3*x) < 0

( 18-3*x )

18-3*x < 0 // - 18

-3*x < -18 // : -3

x > -18/(-3)

x > 6

( 3 )

3 < 0

x belongs to the empty set

	(-oo:6)	(6:+oo)
18-3*x	+	-
3	+	+


x in (6:+oo)

(6:+oo)

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