2/3(6y-9)=1/2(8y-4)

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Solution for 2/3(6y-9)=1/2(8y-4) equation: 



2/3(6y-9)=1/2(8y-4)

We move all terms to the left:

2/3(6y-9)-(1/2(8y-4))=0



Domain of the equation: 3(6y-9)!=0

y∈R





Domain of the equation: 2(8y-4))!=0

y∈R



We calculate fractions


(4y8/(3(6y-9)*2(8y-4)))+(-3y6/(3(6y-9)*2(8y-4)))=0



We calculate terms in parentheses: +(4y8/(3(6y-9)*2(8y-4))), so:

4y8/(3(6y-9)*2(8y-4))

We multiply all the terms by the denominator


4y8

We add all the numbers together, and all the variables

4y^8

We do not support eypression: y^8

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