2/3(6x-3)=x+5(x+8)-2x

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Solution for 2/3(6x-3)=x+5(x+8)-2x equation: 


x in (-oo:+oo)

(2/3)*(6*x-3) = 5*(x+8)+x-(2*x) // - 5*(x+8)+x-(2*x)

(2/3)*(6*x-3)-(5*(x+8))-x+2*x = 0

(2/3)*(6*x-3)-5*(x+8)-x+2*x = 0

2/3*(6*x-3)-5*(x+8)-x+2*x = 0

2/3*(6*x-3)-5*(x+8)-x+2*x = 0

2*x-x-x-42 = 0

2*x-2*x-42 = 0

-42 = 0

-42 = 0

x belongs to the empty set

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