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x in (-oo:+oo)
(2/3)*(6*x-(9*x)-(15*y)) = 0
(2/3)*(6*x-9*x-15*y) = 0
2/3*(-3*x-15*y) = 0
( -3*x-15*y )
-3*x-15*y = 0 // + -15*y
-3*x = -(-15*y) // : -3
x = (-(-15*y))/(-3)
x = -5*y
( 2/3 )
2/3 = 0
x belongs to the empty set
x = -5*y
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