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2/3(6x+9)+2x-5=3(x-2)+1/2(2x-4)
We move all terms to the left:
2/3(6x+9)+2x-5-(3(x-2)+1/2(2x-4))=0
Domain of the equation: 3(6x+9)!=0
x∈R
Domain of the equation: 2(2x-4))!=0We add all the numbers together, and all the variables
x∈R
2x+2/3(6x+9)-(3(x-2)+1/2(2x-4))-5=0
We calculate fractions
2x+(4x2/(3(6x+9)*2(2x-4)))+(-(3x+3x6)/(3(6x+9)*2(2x-4)))-5=0
We calculate terms in parentheses: +(4x2/(3(6x+9)*2(2x-4))), so:
4x2/(3(6x+9)*2(2x-4))
We multiply all the terms by the denominator
4x2
We add all the numbers together, and all the variables
4x^2
Back to the equation:
+(4x^2)
We calculate terms in parentheses: +(-(3x+3x6)/(3(6x+9)*2(2x-4))), so:
-(3x+3x6)/(3(6x+9)*2(2x-4))
We add all the numbers together, and all the variables
-(+3x+3x^6)/(3(6x+9)*2(2x-4))
We multiply all the terms by the denominator
-(+3x+3x^6)
We do not support expression: x^6
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