2/3(6m-9)=-17-18m

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Solution for 2/3(6m-9)=-17-18m equation: 



2/3(6m-9)=-17-18m

We move all terms to the left:

2/3(6m-9)-(-17-18m)=0



Domain of the equation: 3(6m-9)!=0

m∈R



We add all the numbers together, and all the variables

2/3(6m-9)-(-18m-17)=0

We get rid of parentheses

2/3(6m-9)+18m+17=0

We multiply all the terms by the denominator


18m*3(6m-9)+17*3(6m-9)+2=0

Wy multiply elements

54m^2(6+51m(6+2=0

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