2/3(6j+9)=3j+7)

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Solution for 2/3(6j+9)=3j+7) equation: 



2/3(6j+9)=3j+7)

We move all terms to the left:

2/3(6j+9)-(3j+7))=0



Domain of the equation: 3(6j+9)!=0

j∈R



We get rid of parentheses

2/3(6j+9)-3j-7)=0

We multiply all the terms by the denominator


-3j*3(6j+9)-7)*3(6j+2+9)=0

We add all the numbers together, and all the variables

-3j*3(6j+9)-7)*3(6j+11)=0

We add all the numbers together, and all the variables

-3j*3(6j+9)-7)*3(6j=0

Wy multiply elements

-9j^2(6-7)*3(6j=0

We add all the numbers together, and all the variables

-9j^2(-1)*3(6j=0

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