2/3(6j+9)=+3j+7

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Solution for 2/3(6j+9)=+3j+7 equation: 



2/3(6j+9)=+3j+7

We move all terms to the left:

2/3(6j+9)-(+3j+7)=0



Domain of the equation: 3(6j+9)!=0

j∈R



We add all the numbers together, and all the variables

2/3(6j+9)-(3j+7)=0

We get rid of parentheses

2/3(6j+9)-3j-7=0

We multiply all the terms by the denominator


-3j*3(6j+9)-7*3(6j+9)+2=0

Wy multiply elements

-9j^2(6-21j(6+2=0

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