2/3(6a+3b)-1/2(9-2b)

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Solution for 2/3(6a+3b)-1/2(9-2b) equation: 


x in (-oo:+oo)

(2/3)*(6*a+3*b)-((1/2)*(9-(2*b))) = 0

(2/3)*(6*a+3*b)+(-1/2)*(9-2*b) = 0

2/3*(6*a+3*b)-1/2*(9-2*b) = 0

2/3*(6*a+3*b)-1/2*(9-2*b) = 0

4*a+3*b-9/2 = 0

4*a+3*b-9/2 = 0

x belongs to the empty set

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