2/3(6-9)=-1/5(15x+10)

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Solution for 2/3(6-9)=-1/5(15x+10) equation: 



2/3(6-9)=-1/5(15x+10)

We move all terms to the left:

2/3(6-9)-(-1/5(15x+10))=0



Domain of the equation: 5(15x+10))!=0

x∈R



We add all the numbers together, and all the variables

-(-1/5(15x+10))+2/3(-3)=0

We calculate fractions


()/(5(15x+10))*3()+(10x1/(5(15x+10))*3()=0



We calculate terms in parentheses: +()/(5(15x+10))*3(), so:

)/(5(15x+10))*3(

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()





We calculate terms in parentheses: +(10x1/(5(15x+10))*3(), so:

10x1/(5(15x+10))*3(

We multiply all the terms by the denominator


10x1

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)



We add all the numbers together, and all the variables

10x=0

x=0/10

x=0

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