2/3(5c-18)=7

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Solution for 2/3(5c-18)=7 equation: 



2/3(5c-18)=7

We move all terms to the left:

2/3(5c-18)-(7)=0



Domain of the equation: 3(5c-18)!=0

c∈R



We multiply all the terms by the denominator


-7*3(5c-18)+2=0

Wy multiply elements

-21c(5+2=0

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