2/3(5c-1)=-3/5(c+2)

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Solution for 2/3(5c-1)=-3/5(c+2) equation: 



2/3(5c-1)=-3/5(c+2)

We move all terms to the left:

2/3(5c-1)-(-3/5(c+2))=0



Domain of the equation: 3(5c-1)!=0

c∈R





Domain of the equation: 5(c+2))!=0

c∈R



We calculate fractions


(10cc/(3(5c-1)*5(c+2)))+(-(-9c5)/(3(5c-1)*5(c+2)))=0



We calculate terms in parentheses: +(10cc/(3(5c-1)*5(c+2))), so:

10cc/(3(5c-1)*5(c+2))

We multiply all the terms by the denominator


10cc

Back to the equation:

+(10cc)





We calculate terms in parentheses: +(-(-9c5)/(3(5c-1)*5(c+2))), so:

-(-9c5)/(3(5c-1)*5(c+2))

We add all the numbers together, and all the variables

-(-9c^5)/(3(5c-1)*5(c+2))

We multiply all the terms by the denominator


-(-9c^5)

We do not support ecpression: c^5

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