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2/3(4x-1)-3x=5/4-(x+2)
We move all terms to the left:
2/3(4x-1)-3x-(5/4-(x+2))=0
Domain of the equation: 3(4x-1)!=0
x∈R
Domain of the equation: 4-(x+2))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-(x+2))!=-4
x∈R
-3x+2/3(4x-1)-(5/4-(x+2))=0
We calculate fractions
-3x+(-(x+2))+2*4)/(48x-(x+2))-12)+(-15x4/(48x-(x+2))-12)=0
We calculate terms in parentheses: +(-(x+2)), so:We get rid of parentheses
-(x+2)
We get rid of parentheses
-x-2
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
+(-1x-2)
-3x-1x+2*4)/(48x-(x+2))-12)+(-15x4/(48x-x-2-2))-12=0
We multiply all the terms by the denominator
-3x*(48x-1x*(48x+2*4)-(x+2))-15x4-x*(48x-2*(48x-2)-12)*(48x-12)+(=0
We add all the numbers together, and all the variables
-3x*(48x-1x*(48x+8)-(x+2))-15x4-x*(48x-2*(48x-2)-12)*(48x-12)+(=0
We add all the numbers together, and all the variables
-15x^4-3x*(48x-1x*(48x+8)-(x+2))-x*(48x-2*(48x-2)-12)*(48x-12)=0
We do not support expression: x^4
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