2/3(4m-18)=15

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Solution for 2/3(4m-18)=15 equation: 



2/3(4m-18)=15

We move all terms to the left:

2/3(4m-18)-(15)=0



Domain of the equation: 3(4m-18)!=0

m∈R



We multiply all the terms by the denominator


-15*3(4m-18)+2=0

Wy multiply elements

-45m(4+2=0

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