2/3(4b+8)-2=1/2(10+b)

Solution for 2/3(4b+8)-2=1/2(10+b) equation:

2/3(4b+8)-2=1/2(10+b)

We move all terms to the left:

2/3(4b+8)-2-(1/2(10+b))=0


Domain of the equation: 3(4b+8)!=0

b∈R



Domain of the equation: 2(10+b))!=0

b∈R


We add all the numbers together, and all the variables

2/3(4b+8)-(1/2(b+10))-2=0

We calculate fractions


(4bb/(3(4b+8)*2(b+10)))+(-3b4/(3(4b+8)*2(b+10)))-2=0


We calculate terms in parentheses: +(4bb/(3(4b+8)*2(b+10))), so:

4bb/(3(4b+8)*2(b+10))

We multiply all the terms by the denominator


4bb

Back to the equation:

+(4bb)



We calculate terms in parentheses: +(-3b4/(3(4b+8)*2(b+10))), so:

-3b4/(3(4b+8)*2(b+10))

We multiply all the terms by the denominator


-3b4

We add all the numbers together, and all the variables

-3b^4

We do not support ebpression: b^4