2/3(3y-6)+4(5y-8)=92

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Solution for 2/3(3y-6)+4(5y-8)=92 equation:



2/3(3y-6)+4(5y-8)=92
We move all terms to the left:
2/3(3y-6)+4(5y-8)-(92)=0
Domain of the equation: 3(3y-6)!=0
y∈R
We multiply parentheses
2/3(3y-6)+20y-32-92=0
We multiply all the terms by the denominator
20y*3(3y-6)-32*3(3y-6)-92*3(3y-6)+2=0
Wy multiply elements
60y^2(3-96y(3-276y(3+2=0

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