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2/3(3x-5)-3(2x-3)=3/1
We move all terms to the left:
2/3(3x-5)-3(2x-3)-(3/1)=0
Domain of the equation: 3(3x-5)!=0We add all the numbers together, and all the variables
x∈R
2/3(3x-5)-3(2x-3)-0=0
We add all the numbers together, and all the variables
2/3(3x-5)-3(2x-3)=0
We multiply parentheses
2/3(3x-5)-6x+9=0
We multiply all the terms by the denominator
-6x*3(3x-5)+9*3(3x-5)+2=0
Wy multiply elements
-18x^2(3+27x(3+2=0
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