2/3(3x-12)+2x=-2x+40

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Solution for 2/3(3x-12)+2x=-2x+40 equation: 



2/3(3x-12)+2x=-2x+40

We move all terms to the left:

2/3(3x-12)+2x-(-2x+40)=0



Domain of the equation: 3(3x-12)!=0

x∈R



We add all the numbers together, and all the variables

2x+2/3(3x-12)-(-2x+40)=0

We get rid of parentheses

2x+2/3(3x-12)+2x-40=0

We multiply all the terms by the denominator


2x*3(3x-12)+2x*3(3x-12)-40*3(3x-12)+2=0

Wy multiply elements

6x^2(3+6x^2(3-120x(3+2=0

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