2/3(3x+9)=2x+18

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Solution for 2/3(3x+9)=2x+18 equation: 



2/3(3x+9)=2x+18

We move all terms to the left:

2/3(3x+9)-(2x+18)=0



Domain of the equation: 3(3x+9)!=0

x∈R



We get rid of parentheses

2/3(3x+9)-2x-18=0

We multiply all the terms by the denominator


-2x*3(3x+9)-18*3(3x+9)+2=0

Wy multiply elements

-6x^2(3-54x(3+2=0

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