2/3(3x+12)=6x-16

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Solution for 2/3(3x+12)=6x-16 equation: 



2/3(3x+12)=6x-16

We move all terms to the left:

2/3(3x+12)-(6x-16)=0



Domain of the equation: 3(3x+12)!=0

x∈R



We get rid of parentheses

2/3(3x+12)-6x+16=0

We multiply all the terms by the denominator


-6x*3(3x+12)+16*3(3x+12)+2=0

Wy multiply elements

-18x^2(3+48x(3+2=0

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