2/3(3t+9t)=40

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Solution for 2/3(3t+9t)=40 equation:

2/3(3t+9t)=40
We move all terms to the left:
2/3(3t+9t)-(40)=0

Domain of the equation: 3(3t+9t)!=0
t∈R

We add all the numbers together, and all the variables
2/3(+12t)-40=0
We multiply all the terms by the denominator

-40*3(+12t)+2=0
Wy multiply elements
-120t(++2=0
We use the square of the difference formula
-120t(+2=0

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