2/3(3-c)=8+1/6c

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Solution for 2/3(3-c)=8+1/6c equation: 



2/3(3-c)=8+1/6c

We move all terms to the left:

2/3(3-c)-(8+1/6c)=0



Domain of the equation: 3(3-c)!=0

c∈R





Domain of the equation: 6c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

2/3(-1c+3)-(1/6c+8)=0

We get rid of parentheses

2/3(-1c+3)-1/6c-8=0

We calculate fractions


12c/(-18c^2+54c)+(-3c(-)/(-18c^2+54c)-8=0

We add all the numbers together, and all the variables

12c/(-18c^2+54c)+(-3c0/(-18c^2+54c)-8=0

We calculate fractions

We do not support ecpression: c^3

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