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2/3(2x-3x)=4/3x
We move all terms to the left:
2/3(2x-3x)-(4/3x)=0
Domain of the equation: 3(2x-3x)!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3(-1x)-(+4/3x)=0
We get rid of parentheses
2/3(-1x)-4/3x=0
We calculate fractions
6x/(-9x^2)+(-12x(-)/(-9x^2)=0
We calculate terms in parentheses: +(-12x(-)/(-9x^2), so:We get rid of parentheses
-12x(-)/(-9x^2
We add all the numbers together, and all the variables
-12x0/(-9x^2
We multiply all the terms by the denominator
-12x0
We add all the numbers together, and all the variables
-12x
Back to the equation:
+(-12x)
6x/(-9x^2)-12x=0
We multiply all the terms by the denominator
-12x*(-9x^2)+6x=0
We multiply parentheses
108x^3+6x=0
We do not support expression: x^3
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