2/3(2x-3)-9=3/4(8-2x)

Solution for 2/3(2x-3)-9=3/4(8-2x) equation:

2/3(2x-3)-9=3/4(8-2x)

We move all terms to the left:

2/3(2x-3)-9-(3/4(8-2x))=0


Domain of the equation: 3(2x-3)!=0

x∈R



Domain of the equation: 4(8-2x))!=0

x∈R


We add all the numbers together, and all the variables

2/3(2x-3)-(3/4(-2x+8))-9=0

We calculate fractions


(8x(-)/(3(2x-3)*4(-2x+8)))+(-9x2/(3(2x-3)*4(-2x+8)))-9=0


We calculate terms in parentheses: +(8x(-)/(3(2x-3)*4(-2x+8))), so:

8x(-)/(3(2x-3)*4(-2x+8))

We add all the numbers together, and all the variables

8x0/(3(2x-3)*4(-2x+8))

We multiply all the terms by the denominator


8x0

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)



We calculate terms in parentheses: +(-9x2/(3(2x-3)*4(-2x+8))), so:

-9x2/(3(2x-3)*4(-2x+8))

We multiply all the terms by the denominator


-9x2

We add all the numbers together, and all the variables

-9x^2

Back to the equation:

+(-9x^2)


We get rid of parentheses

-9x^2+8x-9=0

a = -9; b = 8; c = -9;
Δ = b2-4ac
Δ = 82-4·(-9)·(-9)
Δ = -260
Delta is less than zero, so there is no solution for the equation