2/3(2x+12)=16

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Solution for 2/3(2x+12)=16 equation: 



2/3(2x+12)=16

We move all terms to the left:

2/3(2x+12)-(16)=0



Domain of the equation: 3(2x+12)!=0

x∈R



We multiply all the terms by the denominator


-16*3(2x+12)+2=0

Wy multiply elements

-48x(2+2=0

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