2/3(2n+12)-9n=-48

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Solution for 2/3(2n+12)-9n=-48 equation: 



2/3(2n+12)-9n=-48

We move all terms to the left:

2/3(2n+12)-9n-(-48)=0



Domain of the equation: 3(2n+12)!=0

n∈R



We add all the numbers together, and all the variables

-9n+2/3(2n+12)+48=0

We multiply all the terms by the denominator


-9n*3(2n+12)+48*3(2n+12)+2=0

Wy multiply elements

-27n^2(2+144n(2+2=0

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