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2/3(26-5x)-7x/3=1/3(52-17x)
We move all terms to the left:
2/3(26-5x)-7x/3-(1/3(52-17x))=0
Domain of the equation: 3(26-5x)!=0
x∈R
Domain of the equation: 3(52-17x))!=0We add all the numbers together, and all the variables
x∈R
2/3(-5x+26)-7x/3-(1/3(-17x+52))=0
We calculate fractions
(6x(-)/(3(-5x+26)*3*3(-17x+52)))+(-3x0/(3(-5x+26)*3*3(-17x+52)))=0
We calculate terms in parentheses: +(6x(-)/(3(-5x+26)*3*3(-17x+52))), so:
6x(-)/(3(-5x+26)*3*3(-17x+52))
We add all the numbers together, and all the variables
6x0/(3(-5x+26)*3*3(-17x+52))
We multiply all the terms by the denominator
6x0
We add all the numbers together, and all the variables
6x
Back to the equation:
+(6x)
We calculate terms in parentheses: +(-3x0/(3(-5x+26)*3*3(-17x+52))), so:We get rid of parentheses
-3x0/(3(-5x+26)*3*3(-17x+52))
We multiply all the terms by the denominator
-3x0
We add all the numbers together, and all the variables
-3x
Back to the equation:
+(-3x)
6x-3x=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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