2/3(26-5x)-7/3x=1/3(52-17x)

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Solution for 2/3(26-5x)-7/3x=1/3(52-17x) equation: 



2/3(26-5x)-7/3x=1/3(52-17x)

We move all terms to the left:

2/3(26-5x)-7/3x-(1/3(52-17x))=0



Domain of the equation: 3(26-5x)!=0

x∈R





Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3(52-17x))!=0

x∈R



We add all the numbers together, and all the variables

2/3(-5x+26)-7/3x-(1/3(-17x+52))=0

We calculate fractions


-63x^2(-)/(3(-5x+26)*3x*3(-17x+52)))+(+54x^2/(3(-5x+26)*3x*3(-17x+52)))+(-(1*3(-5x+26)*3x)/(3(-5x+26)*3x*3(-17x+52)))=0



We calculate terms in parentheses: -(1*3(-5x+26)*3x)/(3(-5x+26)*3x*3(-17x+52))), so:

1*3(-5x+26)*3x)/(3(-5x+26)*3x*3(-17x+52))

We multiply all the terms by the denominator


1*3(-5x+26)*3x)

Wy multiply elements

9x^2(-

Back to the equation:

-(9x^2(-)



We add all the numbers together, and all the variables

-63x^20/(3(-5x+26)*3x*3(-17x+52)))+(+54x^2/(3(-5x+26)*3x*3(-17x+52)))+(-(9x^20=0

We multiply all the terms by the denominator


-63x^20+54x^2-(9x^20*(3(-5x+26)*3x*3(-17x+52)))+(=0



We calculate terms in parentheses: -(9x^20*(3(-5x+26)*3x*3(-17x+52))), so:

9x^20*(3(-5x+26)*3x*3(-17x+52))

We do not support expression: x^20

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