2/3(24x+24)-18=3/4(28x-12)

Solution for 2/3(24x+24)-18=3/4(28x-12) equation:

2/3(24x+24)-18=3/4(28x-12)

We move all terms to the left:

2/3(24x+24)-18-(3/4(28x-12))=0


Domain of the equation: 3(24x+24)!=0

x∈R



Domain of the equation: 4(28x-12))!=0

x∈R


We calculate fractions


(8x2/(3(24x+24)*4(28x-12)))+(-9x2/(3(24x+24)*4(28x-12)))-18=0


We calculate terms in parentheses: +(8x2/(3(24x+24)*4(28x-12))), so:

8x2/(3(24x+24)*4(28x-12))

We multiply all the terms by the denominator


8x2

We add all the numbers together, and all the variables

8x^2

Back to the equation:

+(8x^2)



We calculate terms in parentheses: +(-9x2/(3(24x+24)*4(28x-12))), so:

-9x2/(3(24x+24)*4(28x-12))

We multiply all the terms by the denominator


-9x2

We add all the numbers together, and all the variables

-9x^2

Back to the equation:

+(-9x^2)


We add all the numbers together, and all the variables

8x^2+(-9x^2)-18=0

We get rid of parentheses

8x^2-9x^2-18=0

We add all the numbers together, and all the variables

-1x^2-18=0

a = -1; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·(-1)·(-18)
Δ = -72
Delta is less than zero, so there is no solution for the equation