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2/3(15x-9)-6x+2=0.2(10x+5)+2x-2
We move all terms to the left:
2/3(15x-9)-6x+2-(0.2(10x+5)+2x-2)=0
Domain of the equation: 3(15x-9)!=0We add all the numbers together, and all the variables
x∈R
-6x+2/3(15x-9)-(0.2(10x+5)+2x-2)+2=0
We multiply all the terms by the denominator
-6x*3(15x-9)-((0.2(10x+5)+2x-2))*3(15x-9)+2*3(15x-9)+2=0
We calculate terms in parentheses: -((0.2(10x+5)+2x-2))*3(15x-9), so:Wy multiply elements
(0.2(10x+5)+2x-2))*3(15x-9
-18x^2(1-((0.2(10x+5)+2x-2))*3(15x-9)+6x(1+2=0
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