2/3(1+x)=-1/2x

Solution for 2/3(1+x)=-1/2x equation:

2/3(1+x)=-1/2x

We move all terms to the left:

2/3(1+x)-(-1/2x)=0


Domain of the equation: 3(1+x)!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/3(x+1)-(-1/2x)=0

We get rid of parentheses

2/3(x+1)+1/2x=0

We calculate fractions


4x/(6x^2+6x)+(3xx/(6x^2+6x)=0


We calculate terms in parentheses: +(3xx/(6x^2+6x), so:

3xx/(6x^2+6x

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)


We multiply all the terms by the denominator


4x+3xx*(6x^2+6x)=0

We multiply parentheses

18x^3+18x^2+4x=0

We do not support expression: x^3