2/3(-x+2)+1/2(x+2)=1/6

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Solution for 2/3(-x+2)+1/2(x+2)=1/6 equation: 



2/3(-x+2)+1/2(x+2)=1/6

We move all terms to the left:

2/3(-x+2)+1/2(x+2)-(1/6)=0



Domain of the equation: 3(-x+2)!=0

x∈R





Domain of the equation: 2(x+2)!=0

x∈R



We add all the numbers together, and all the variables

2/3(-1x+2)+1/2(x+2)-(+1/6)=0

We get rid of parentheses

2/3(-1x+2)+1/2(x+2)-1/6=0

We calculate fractions


(24xx/(3(-1x+2)*2(x+2)*6)+(18x(-)/(3(-1x+2)*2(x+2)*6)+(-6x^2(-)/(3(-1x+2)*2(x+2)*6)=0



We calculate terms in parentheses: +(24xx/(3(-1x+2)*2(x+2)*6)+(18x(-)/(3(-1x+2)*2(x+2)*6)+(-6x^2(-)/(3(-1x+2)*2(x+2)*6), so:

24xx/(3(-1x+2)*2(x+2)*6)+(18x(-)/(3(-1x+2)*2(x+2)*6)+(-6x^2(-)/(3(-1x+2)*2(x+2)*6

We can not solve this equation

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