2/3(-12+(6x-9))=-18

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Solution for 2/3(-12+(6x-9))=-18 equation: 



2/3(-12+(6x-9))=-18

We move all terms to the left:

2/3(-12+(6x-9))-(-18)=0



Domain of the equation: 3(-12+(6x-9))!=0

x∈R



We add all the numbers together, and all the variables

2/3(-12+(6x-9))+18=0

We multiply all the terms by the denominator


18*3(-12+(6x-9))+2=0

Wy multiply elements

54x(-+2=0

We use the square of the difference formula

54x(-2=0

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