2/2x=2/1x+20

Solution for 2/2x=2/1x+20 equation:

2/2x=2/1x+20

We move all terms to the left:

2/2x-(2/1x+20)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 1x+20)!=0

x∈R


We get rid of parentheses

2/2x-2/1x-20=0

We calculate fractions


2x/2x^2+(-4x)/2x^2-20=0

We multiply all the terms by the denominator


2x+(-4x)-20*2x^2=0

Wy multiply elements

-40x^2+2x+(-4x)=0

We get rid of parentheses

-40x^2+2x-4x=0

We add all the numbers together, and all the variables

-40x^2-2x=0

a = -40; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-40)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-40}=\frac{0}{-80}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-40}=\frac{4}{-80}
=-1/20
$