2/2b-8=-1/5b=7

Solution for 2/2b-8=-1/5b=7 equation:

2/2b-8=-1/5b=7

We move all terms to the left:

2/2b-8-(-1/5b)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R


We get rid of parentheses

2/2b+1/5b-8=0

We calculate fractions


10b/10b^2+2b/10b^2-8=0

We multiply all the terms by the denominator


10b+2b-8*10b^2=0

We add all the numbers together, and all the variables

12b-8*10b^2=0

Wy multiply elements

-80b^2+12b=0

a = -80; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-80)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-80}=\frac{-24}{-160}
=3/20
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-80}=\frac{0}{-160}
=0
$