2/2b+4=2/b-4

Solution for 2/2b+4=2/b-4 equation:

2/2b+4=2/b-4

We move all terms to the left:

2/2b+4-(2/b-4)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



Domain of the equation: b-4)!=0

b∈R


We get rid of parentheses

2/2b-2/b+4+4=0

We calculate fractions


2b/2b^2+(-4b)/2b^2+4+4=0

We add all the numbers together, and all the variables

2b/2b^2+(-4b)/2b^2+8=0

We multiply all the terms by the denominator


2b+(-4b)+8*2b^2=0

Wy multiply elements

16b^2+2b+(-4b)=0

We get rid of parentheses

16b^2+2b-4b=0

We add all the numbers together, and all the variables

16b^2-2b=0

a = 16; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·16·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*16}=\frac{0}{32}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*16}=\frac{4}{32}
=1/8
$