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2/2-3x=-2/4x
We move all terms to the left:
2/2-3x-(-2/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-3x-(-2/4x)+1=0
We get rid of parentheses
-3x+2/4x+1=0
We multiply all the terms by the denominator
-3x*4x+1*4x+2=0
Wy multiply elements
-12x^2+4x+2=0
a = -12; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·(-12)·2
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{7}}{2*-12}=\frac{-4-4\sqrt{7}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{7}}{2*-12}=\frac{-4+4\sqrt{7}}{-24} $
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