2/12k=22

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Solution for 2/12k=22 equation: 



2/12k=22

We move all terms to the left:

2/12k-(22)=0



Domain of the equation: 12k!=0

k!=0/12

k!=0

k∈R



We multiply all the terms by the denominator


-22*12k+2=0

Wy multiply elements

-264k+2=0

We move all terms containing k to the left, all other terms to the right

-264k=-2

k=-2/-264

k=1/132

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