2/11p+7=1/5p

Solution for 2/11p+7=1/5p equation:

2/11p+7=1/5p

We move all terms to the left:

2/11p+7-(1/5p)=0


Domain of the equation: 11p!=0

p!=0/11

p!=0

p∈R



Domain of the equation: 5p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

2/11p-(+1/5p)+7=0

We get rid of parentheses

2/11p-1/5p+7=0

We calculate fractions


10p/55p^2+(-11p)/55p^2+7=0

We multiply all the terms by the denominator


10p+(-11p)+7*55p^2=0

Wy multiply elements

385p^2+10p+(-11p)=0

We get rid of parentheses

385p^2+10p-11p=0

We add all the numbers together, and all the variables

385p^2-1p=0

a = 385; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·385·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*385}=\frac{0}{770}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*385}=\frac{2}{770}
=1/385
$