2/11m+16=4+6/22m

Solution for 2/11m+16=4+6/22m equation:

2/11m+16=4+6/22m

We move all terms to the left:

2/11m+16-(4+6/22m)=0


Domain of the equation: 11m!=0

m!=0/11

m!=0

m∈R



Domain of the equation: 22m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2/11m-(6/22m+4)+16=0

We get rid of parentheses

2/11m-6/22m-4+16=0

We calculate fractions


44m/242m^2+(-66m)/242m^2-4+16=0

We add all the numbers together, and all the variables

44m/242m^2+(-66m)/242m^2+12=0

We multiply all the terms by the denominator


44m+(-66m)+12*242m^2=0

Wy multiply elements

2904m^2+44m+(-66m)=0

We get rid of parentheses

2904m^2+44m-66m=0

We add all the numbers together, and all the variables

2904m^2-22m=0

a = 2904; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·2904·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*2904}=\frac{0}{5808}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*2904}=\frac{44}{5808}
=1/132
$