2/11m+16=4+6/11mm=

Solution for 2/11m+16=4+6/11mm= equation:

2/11m+16=4+6/11mm=

We move all terms to the left:

2/11m+16-(4+6/11mm)=0


Domain of the equation: 11m!=0

m!=0/11

m!=0

m∈R



Domain of the equation: 11mm)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2/11m-(6/11mm+4)+16=0

We get rid of parentheses

2/11m-6/11mm-4+16=0

We calculate fractions


22m/121m^2+(-66m)/121m^2-4+16=0

We add all the numbers together, and all the variables

22m/121m^2+(-66m)/121m^2+12=0

We multiply all the terms by the denominator


22m+(-66m)+12*121m^2=0

Wy multiply elements

1452m^2+22m+(-66m)=0

We get rid of parentheses

1452m^2+22m-66m=0

We add all the numbers together, and all the variables

1452m^2-44m=0

a = 1452; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·1452·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*1452}=\frac{0}{2904}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*1452}=\frac{88}{2904}
=1/33
$